Correct Answer: A

Rationale: Adenocarcinoma is the correct answer because it is a type of lung cancer that originates in the cells lining the bronchi and bronchioles. Adenocarcinoma is one of the most common types of lung cancer, often found in non-smokers and more frequently in women. Small cell lung cancer (Choice B) typically starts in the bronchi, but it is characterized by its rapid growth and tendency to spread quickly. Squamous cell carcinoma (Choice C) usually begins in the squamous cells lining the bronchi and is strongly associated with smoking. Mesothelioma (Choice D) is a cancer that affects the lining of certain organs like the lungs, often caused by asbestos exposure, but it does not specifically start in the cells lining the bronchi and bronchioles.

Correct Answer: A

Rationale: The correct answer is A, Coronary artery disease (CAD). CAD occurs when the coronary arteries are narrowed or blocked, reducing blood flow to the heart muscle and increasing the risk of chest pain or heart attack. Choice B, Atherosclerosis, is a condition characterized by the hardening and narrowing of arteries due to the buildup of plaque. Choices C and D, Pulmonary embolism and Pulmonary hypertension, involve issues related to the lungs and not the coronary arteries.

Correct Answer: A

Rationale: An electrocardiogram (ECG or EKG) is used to measure the heart's electrical activity, aiding in the detection of arrhythmias and other heart conditions. Choice B, a chest X-ray, is not used to measure electrical activity but to visualize the structures of the chest. Choice C, a stress test, evaluates the heart's response to exertion and is not primarily focused on measuring electrical activity. Choice D, an arterial blood gas (ABG) test, is used to assess oxygen and carbon dioxide levels in the blood, not the heart's electrical activity.

Correct Answer: A

Rationale: The correct answer is A: Arrhythmia. Arrhythmia is a broad term that refers to any irregularity in the heart's rhythm, which can manifest as a heartbeat that is too fast (tachycardia), too slow (bradycardia), or irregular. Choice B, Bradycardia, specifically denotes a slow heart rate, while choice C, Tachycardia, refers to a fast heart rate. Choice D, Conductivity, is not the correct term to describe an abnormal heartbeat characterized by speed irregularities.

Correct Answer: A

Rationale: The correct answer is A: Avoid foods high in vitamin K. Warfarin is an anticoagulant medication, and vitamin K can counteract its effects. Therefore, it is important for clients taking warfarin to avoid foods high in vitamin K to maintain the medication's effectiveness. Choice B is incorrect because warfarin should be taken consistently as prescribed, regardless of food intake. Choice C is incorrect because while consistency in timing is important, it is not specific to the effectiveness of warfarin. Choice D is incorrect because clients should never increase the dose of warfarin on their own, especially to make up for a missed dose, as it can lead to serious bleeding risks.