ATI RN
microbiology basic and clinical principles test bank Questions
Question 1 of 9
The organism that is responsible for the vast majority of cases of fungal vaginitis is:
Correct Answer: D
Rationale: The correct answer is D: Propionibacterium acnes. This bacterium is not a fungus, but a common skin bacteria. Fungal vaginitis is typically caused by Candida albicans or other fungal species, not by bacteria like Escherichia coli, Streptococcus agalactiae, or Klebsiella oxytoca. Propionibacterium acnes is not associated with vaginal infections, making it the correct answer in this context.
Question 2 of 9
A patient with fever and sore throat had a throat culture revealing Gram-positive cocci in chains. The bacteria were catalase-negative and beta-hemolytic. What is the most likely causative agent?
Correct Answer: A
Rationale: The correct answer is A: Streptococcus pyogenes. 1. Gram-positive cocci in chains: characteristic of Streptococcus species. 2. Catalase-negative: Streptococcus species are catalase-negative. 3. Beta-hemolytic: S. pyogenes is beta-hemolytic on blood agar. Therefore, S. pyogenes fits all these criteria. B: Streptococcus pneumoniae is catalase-negative but alpha-hemolytic, not beta-hemolytic. C: Enterococcus faecalis is catalase-negative, but not typically beta-hemolytic or in chains. D: Staphylococcus aureus is catalase-positive and not in chains.
Question 3 of 9
Almost half of all the STIs diagnosed in the United States are among:
Correct Answer: C
Rationale: The correct answer is C: young adults. Young adults are at a higher risk for sexually transmitted infections (STIs) due to factors such as engaging in risky sexual behaviors, lack of awareness, and inconsistent condom use. They are more likely to have multiple sexual partners and are less likely to seek regular STI screenings. Adolescents, while also at risk, may not make up almost half of all STI cases in the U.S. The elderly, on the other hand, are generally at a lower risk due to lower levels of sexual activity compared to young adults.
Question 4 of 9
For tuberculosis prevention the newborns got an injection of a vaccine. What vaccine was used?
Correct Answer: A
Rationale: The correct answer is A: BCG. BCG vaccine is commonly used for tuberculosis prevention because it provides immunity against Mycobacterium tuberculosis. Mantoux is a test, not a vaccine. DTaP vaccine is for diphtheria, tetanus, and pertussis, not tuberculosis. Anatoxin is a type of toxoid vaccine, not used for tuberculosis prevention. BCG vaccine has been shown to be effective in preventing severe forms of tuberculosis in infants, making it the appropriate choice in this scenario.
Question 5 of 9
The bacteriological laboratory needs to prepare for analysis of materials that are suspected to be contaminated with spores of anthrax causative agent. What diagnostic preparation allows for quick detection of these spores?
Correct Answer: D
Rationale: The correct answer is D: Monoclonal antibodies to anthrax causative agent. Monoclonal antibodies are highly specific for detecting anthrax spores, providing quick and accurate results. They bind only to the anthrax causative agent, allowing for precise identification. Choice A (Anti-anthrax fluorescent serum) is incorrect because it is not as specific and sensitive as monoclonal antibodies. Choice B (Standard anthrax antigen) is incorrect as it is used to stimulate antibody production in the body, not for direct detection of spores. Choice C (Anti-anthrax immunoglobulin) is incorrect as it is a general term for antibodies and may not be specific to anthrax spores. In summary, monoclonal antibodies are the most suitable option for quick and accurate detection of anthrax spores due to their high specificity and sensitivity.
Question 6 of 9
Which bacteria are capable of producing endospores?
Correct Answer: B
Rationale: The correct answer is B: Clostridium botulinum. This bacterium belongs to the Clostridium genus, known for its ability to produce endospores. Endospores are dormant, resistant structures that help bacteria survive harsh conditions. Staphylococcus aureus (A), Escherichia coli (C), and Neisseria gonorrhoeae (D) do not produce endospores. Staphylococcus aureus is a gram-positive bacterium known for causing various infections, but it does not form endospores. Escherichia coli is a gram-negative bacterium commonly found in the intestines of humans and animals, but it does not produce endospores. Neisseria gonorrhoeae is a gram-negative bacterium that causes the sexually transmitted infection gonorrhea, but it also does not form endospores.
Question 7 of 9
Formic acid is a fermentation product of
Correct Answer: D
Rationale: Step 1: Formic acid is produced during fermentation by Actinomyces. Step 2: Actinomyces are known to produce organic acids like formic acid through fermentation. Step 3: Other choices like Streptococcus, Klebsiella, and Clostridium are not typically associated with formic acid production. Step 4: Actinomyces is the most likely candidate based on its fermentation capabilities. Summary: Actinomyces is the correct answer because it is known to produce formic acid during fermentation, while the other choices lack this specific metabolic function.
Question 8 of 9
The cell envelope of Gram-negative bacteria is composed of:
Correct Answer: A
Rationale: The correct answer is A because Gram-negative bacteria have a unique cell envelope structure consisting of a cytoplasmic membrane, a peptidoglycan layer, and an outer membrane. The cytoplasmic membrane is the innermost layer that separates the cytoplasm from the external environment. The peptidoglycan layer provides structural support to the cell. The outer membrane acts as an additional protective barrier and contains lipopolysaccharides. Choice B is incorrect because Gram-negative bacteria have an outer membrane in addition to the cytoplasmic membrane and peptidoglycan layer. Choice C is incorrect because Gram-negative bacteria have more than just a peptidoglycan layer in their cell envelope. Choice D is incorrect as the cell envelope of Gram-negative bacteria does have specific components.
Question 9 of 9
Streptococcus pneumoniae are:
Correct Answer: B
Rationale: The correct answer is B: Alpha-hemolytic streptococci. Streptococcus pneumoniae are classified as alpha-hemolytic streptococci based on their ability to partially break down red blood cells, causing a greenish discoloration on blood agar plates. This distinguishes them from beta-hemolytic streptococci, which completely break down red blood cells. Streptococcus pneumoniae are not resistant to bile (choice A), as they are bile soluble. They are not stained by the Ziehl-Neelsen staining method (choice C), which is used for acid-fast bacteria such as Mycobacterium tuberculosis. They are sensitive to optochin (choice D), which is a key differentiating factor in identifying them from other alpha-hemolytic streptococci.