On examination of a 6-year-old child the doctor noticed greyish film on the child's tonsils. Microscopy of the smear stained by Neisser method detected there Corynebacterium diphtheria. What morphologic feature was the most indicative for determining the type of the agent?

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Question 1 of 9

On examination of a 6-year-old child the doctor noticed greyish film on the child's tonsils. Microscopy of the smear stained by Neisser method detected there Corynebacterium diphtheria. What morphologic feature was the most indicative for determining the type of the agent?

Correct Answer: C

Rationale: The correct answer is C: Polar placement of volutin granules. This feature is indicative of Corynebacterium diphtheria. Volutin granules are metachromatic granules found in the polar region of the bacterial cell, which is characteristic of this species. This feature helps differentiate it from other bacteria. Explanation: A: Fence-like position of the agent's cells is not a specific morphologic feature of Corynebacterium diphtheria. B: Spores that exceed cells in diameter is not a characteristic feature of Corynebacterium diphtheria. D: Presence of the capsule is not a distinguishing morphologic feature of Corynebacterium diphtheria. In summary, the polar placement of volutin granules is the most indicative feature for determining the type of agent as Corynebacterium diphtheria, making it the correct choice.

Question 2 of 9

The bacterial endospore is primarily composed of:

Correct Answer: B

Rationale: The correct answer is B: peptidoglycan and calcium dipicolinate. Bacterial endospores are resistant structures formed by certain bacterial species under unfavorable conditions. Peptidoglycan provides structural support, while calcium dipicolinate aids in heat resistance. Lipid bilayers (choice A) are not a primary component. Capsular polysaccharides (choice C) are part of the bacterial capsule, not the endospore. Teichoic acid (choice D) is a component of the cell wall, not the endospore.

Question 3 of 9

The total magnification of an object viewed with a compound microscope with an ocular lens of ×10 and an objective lens of ×40 is ×__________.

Correct Answer: C

Rationale: To calculate the total magnification, we multiply the magnification of the ocular lens by the magnification of the objective lens. In this case, 10 (ocular) x 40 (objective) = 400. This is why choice C (400) is correct. Choices A, B, and D are incorrect because they do not represent the correct calculation of total magnification based on the given magnification powers of the ocular and objective lenses.

Question 4 of 9

Legionellosis has the following clinical forms:

Correct Answer: A

Rationale: Step 1: Legionellosis is caused by the Legionella bacteria. Step 2: Legionellosis has two main clinical forms - Legionnaires disease and Pontiac fever. Step 3: Legionnaires disease presents with severe pneumonia symptoms, while Pontiac fever is a milder flu-like illness. Step 4: Therefore, the correct answer is A: Legionnaires disease and Pontiac fever. Summary: - Choice B (Skin and intestinal form) is incorrect as Legionellosis primarily affects the lungs. - Choice C (Lymphatic, lung, and intestinal forms) is incorrect as it does not accurately represent the clinical forms of Legionellosis. - Choice D (None of the above) is incorrect as Legionellosis does have specific clinical forms.

Question 5 of 9

A patient of oral surgery department has developed a purulent complication. Bacteriological analysis of the wound discharge allowed to isolate a culture producing a blue-and-green pigment. Which of the listed microorganisms may be a causative agent of the infection?

Correct Answer: A

Rationale: The correct answer is A: Pseudomonas aeruginosa. Pseudomonas aeruginosa is known for producing a blue-green pigment called pyocyanin, which is characteristic of its colonies. This bacterium is commonly associated with purulent infections, especially in immunocompromised patients. Proteus vulgaris (B) is not typically associated with blue-green pigment production. Bacillus subtilis (C) is not a common pathogen in wound infections. Klebsiella pneumoniae (D) does not produce blue-green pigment and is more commonly associated with respiratory infections. Therefore, based on the clinical presentation and pigment production, Pseudomonas aeruginosa is the most likely causative agent in this case.

Question 6 of 9

Which of these is an early symptom of rabies?

Correct Answer: D

Rationale: The correct answer is D because all of these symptoms are early signs of rabies. A short period of depression, nausea, and restlessness are common initial symptoms of rabies infection. These symptoms may be followed by more severe manifestations, such as aggression, confusion, and difficulty swallowing. Therefore, option D is the correct choice as it encompasses all the early symptoms of rabies. Options A, B, and C are incorrect as they focus on individual symptoms, whereas rabies typically presents with a combination of these early signs.

Question 7 of 9

Infections of CNS can be caused by:

Correct Answer: D

Rationale: The correct answer is D because all three choices, Clostridium botulinum, Morbillivirus morbillorum, and Clostridium tetani, can cause infections of the central nervous system (CNS). Clostridium botulinum can lead to botulism, which affects the nervous system. Morbillivirus morbillorum can cause measles, which can lead to viral encephalitis. Clostridium tetani can cause tetanus, which affects the CNS by producing neurotoxins. Therefore, all three choices are pathogens that can cause infections of the CNS.

Question 8 of 9

What is the role of bacterial enzymes like amylase and protease?

Correct Answer: C

Rationale: The correct answer is C because bacterial enzymes like amylase and protease catalyze biochemical reactions like digestion. Amylase breaks down carbohydrates, while protease breaks down proteins. This process is essential for bacterial metabolism and nutrient acquisition. Choice A (Break down toxins) is incorrect because bacterial enzymes are primarily involved in nutrient breakdown, not toxin degradation. Choice B (Facilitate movement) is incorrect as enzymes are not directly involved in bacterial movement. Choice D (Promote spore formation) is incorrect because enzymes like amylase and protease are not directly involved in spore formation.

Question 9 of 9

A patient with pneumonia had sputum stained by the Gram method. The smear revealed Gram-positive cocci in pairs with a capsule. What is the most likely causative agent?

Correct Answer: A

Rationale: The correct answer is A: Streptococcus pneumoniae. This bacterium is a common cause of pneumonia and is known to appear as Gram-positive cocci in pairs with a capsule. The presence of a capsule is a key characteristic of S. pneumoniae. Staphylococcus aureus (B) is a Gram-positive cocci but typically does not have a capsule. Neisseria meningitidis (C) is a Gram-negative diplococcus, not a Gram-positive cocci. Klebsiella pneumoniae (D) is a Gram-negative rod, not a Gram-positive cocci. Therefore, based on the staining pattern and the presence of a capsule, Streptococcus pneumoniae is the most likely causative agent in this case.

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