ATI RN
microbiology an introduction 13th edition test bank Questions
Question 1 of 5
Numerous antibodies can be prepared against one antigen, but each binds to unique epitope. How is this antibodies diversity generated?
Correct Answer: D
Rationale: The correct answer is D because antibody diversity is generated by rearrangements of DNA encoding variable regions of heavy and light chains (choice A) and by the combination of different heavy and light chains that form the antigen binding site (choice B). Step 1: DNA rearrangements create different variable regions in heavy and light chains. Step 2: Combination of different heavy and light chains leads to unique antigen binding sites. Step 3: This diversity allows antibodies to bind to different epitopes on the same antigen. Step 4: Choice C is incorrect as antibodies do not physically change shape to bind different epitopes.
Question 2 of 5
A 65 y.o. woman complains of complicated mouth opening following foot trauma 10 days ago. Next day she ate with difficulties, there were muscles tension of back, the back of the head and abdomen. On the third day there was tension of all muscle groups, generalized convulsions every 10-15 min. What is the most probable diagnosis?
Correct Answer: A
Rationale: The most probable diagnosis is Tetanus (Choice A) based on the symptoms described. Tetanus is characterized by muscle stiffness, difficulty opening the mouth (trismus), muscle spasms, and convulsions. The progression of symptoms from muscle tension to generalized convulsions every 10-15 min is classic for tetanus. Tetania (Choice B) is similar but typically presents with more subtle muscle contractions rather than convulsions. Meningoencephalitis (Choice C) presents with fever, headache, and altered mental status, not the muscle symptoms described. Hemorrhagic stroke (Choice D) presents with sudden onset neurological deficits like weakness or sensory changes, not the muscle symptoms described.
Question 3 of 5
Which bacteria are responsible for causing foodborne illnesses?
Correct Answer: D
Rationale: The correct answer is D, "All of the above," because all three bacteria (Salmonella enterica, Clostridium botulinum, Escherichia coli) are known to cause foodborne illnesses. Salmonella causes symptoms like diarrhea, fever, and abdominal cramps. Clostridium botulinum produces a toxin leading to botulism, a severe illness affecting the nervous system. Escherichia coli strains like E. coli O157:H7 can cause food poisoning with symptoms such as bloody diarrhea. Therefore, all the listed bacteria can cause foodborne illnesses due to their ability to contaminate food and infect individuals.
Question 4 of 5
Sputum smears of a patient with chronic pulmonary disease were stained by Ziehl-Neelsen method and analyzed in the bacteriological laboratory. Microscopy revealed red bacillus. What property of tuberculosis myobacteria was found?
Correct Answer: A
Rationale: The correct answer is A: Acid resistance. Tuberculosis mycobacteria have a unique cell wall structure that makes them resistant to acid-fast staining methods like Ziehl-Neelsen. This is due to the high lipid content of their cell walls, specifically mycolic acids, which prevent the penetration of stains and acids. The red bacilli observed in the smear indicate that the mycobacteria retained the primary stain (carbolfuchsin) after acid-alcohol decolorization, confirming their acid resistance. Summary: - Choice A: Acid resistance is correct due to the unique cell wall structure of tuberculosis mycobacteria. - Choice B: Alkali resistance is incorrect as mycobacteria are not known for being resistant to alkalis. - Choice C: Alcohol resistance is incorrect as mycobacteria are not specifically resistant to alcohols. - Choice D: Encapsulation is incorrect as mycobacteria are not encapsulated bacteria.
Question 5 of 5
Numerous antibodies can be prepared against one antigen, but each binds to unique epitope. How is this antibodies diversity generated?
Correct Answer: D
Rationale: The correct answer is D because antibody diversity is generated by rearrangements of DNA encoding variable regions of heavy and light chains (choice A) and by the combination of different heavy and light chains that form the antigen binding site (choice B). Step 1: DNA rearrangements create different variable regions in heavy and light chains. Step 2: Combination of different heavy and light chains leads to unique antigen binding sites. Step 3: This diversity allows antibodies to bind to different epitopes on the same antigen. Step 4: Choice C is incorrect as antibodies do not physically change shape to bind different epitopes.
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