A sample of a finished dosage form was found to be contaminated with some microorganisms exhibiting the following properties: greenish fluorescent colonies of gram-negative nonsporeforming bacilli that grew on the medium for the detection of pyocyanin. The bacilli release the bluegreen pigment into the medium. What microorganisms contaminated the finished dosage form?

Correct Answer: A

Rationale: The correct answer is A: Pseudomonas aeruginosa. Pseudomonas aeruginosa is a gram-negative bacilli that produce pyocyanin, a blue-green pigment. The presence of greenish fluorescent colonies of gram-negative nonsporeforming bacilli that release blue-green pigment matches the characteristics of Pseudomonas aeruginosa. Now, let's analyze the other choices: B: Enterobacteriaceae - While some Enterobacteriaceae can be gram-negative bacilli, they do not typically produce pyocyanin or exhibit the specific characteristics described in the question. C: Staphylococcus aureus - Staphylococcus aureus is a gram-positive cocci, not a gram-negative bacilli. It does not match the given description. D: Staphylococcus epidermidis - Staphylococcus epidermidis is also a gram-positive cocci, not a gram-negative bacilli. It does

Correct Answer: C

Rationale: The correct answer is C because Koch's postulate states that a microorganism must be isolated in pure culture, grown in a laboratory setting, and then inoculated into animals to reproduce the same disease seen in the original host. This step demonstrates a direct cause-and-effect relationship between the isolated microorganism and the disease. Choice A is incorrect because not all cases of a disease may have the same microorganism present. Choice B is incorrect as isolating the microorganism alone does not prove its pathogenicity. Choice D is incorrect as it does not address the need for experimental reproduction of the disease in a new host.

Correct Answer: A

Rationale: The correct answer is A: Clostridium botulinum. This bacterium produces the neurotoxin responsible for botulism. Clostridium perfringens causes gas gangrene, not botulism. Escherichia coli and Salmonella enterica are not associated with botulism. Clostridium botulinum is the only bacterium known to produce the toxin causing botulism.

Correct Answer: D

Rationale: The correct answer is D because Mycobacterium tuberculosis is a straight or slightly curved rod with occasional polymorphism. This bacterium does not conform to the characteristics of gram-negative coccus (A), gram-positive coccus (B), or gram-negative rod (C). Mycobacterium tuberculosis is characterized by its unique cell wall composition, which includes high lipid content and mycolic acids, contributing to its acid-fast staining property. The other choices are incorrect because they do not accurately describe the morphology of Mycobacterium tuberculosis.

Correct Answer: A

Rationale: The correct answer is A: Absence of a cell wall. L-form transformation is a phenomenon where the pathogen loses its cell wall, making it resistant to antibiotics like penicillin. The absence of a cell wall allows the pathogen to survive in a hostile environment. Choice B: Absence of flagella is incorrect because flagella are responsible for motility and not directly related to L-form transformation. Choice C: Absence of a capsule is incorrect as the capsule is a protective layer outside the cell wall and not affected by L-form transformation. Choice D: Absence of a spore is incorrect because spores are a dormant form of bacteria and not related to L-form transformation.

Correct Answer: D

Rationale: The correct answer is D because antibody diversity is generated by rearrangements of DNA encoding variable regions of heavy and light chains (choice A) and by the combination of different heavy and light chains that form the antigen binding site (choice B). Step 1: DNA rearrangements create different variable regions in heavy and light chains. Step 2: Combination of different heavy and light chains leads to unique antigen binding sites. Step 3: This diversity allows antibodies to bind to different epitopes on the same antigen. Step 4: Choice C is incorrect as antibodies do not physically change shape to bind different epitopes.

Correct Answer: A

Rationale: The correct answer is A: Escherichia coli. E. coli is a Gram-negative rod that typically has a greenish hue on MacConkey agar due to its ability to ferment lactose, producing acid that changes the pH indicator to green. E. coli is a common cause of diarrhea, particularly in cases of traveler's diarrhea. Salmonella (B), Shigella (C), and Klebsiella (D) are also Gram-negative rods but do not typically show a greenish hue on MacConkey agar and are less commonly associated with causing diarrhea compared to E. coli.

Correct Answer: B

Rationale: The correct answer is B because transformation in bacteria refers to the uptake of naked DNA from the environment. During transformation, bacteria take up free DNA from their surroundings and incorporate it into their own genome. This mechanism allows bacteria to acquire new genetic material and traits. Explanation for other choices: A: Transfer of DNA via phages refers to transduction, not transformation. C: Transfer of DNA via direct contact is known as conjugation, not transformation. D: Spore formation is a method of bacterial survival but is not related to transformation.

Correct Answer: B

Rationale: The correct answer is B: BCG vaccine. Bacille Calmette-Guérin (BCG) vaccine is used to prevent tuberculosis, which is caused by a bacterium related to anthrax. BCG vaccine can provide cross-protection against anthrax due to its similar mechanisms of action. STI live vaccine (choice A) is used for sexually transmitted infections, not anthrax. Salk vaccine (choice C) is used for polio, and Sabin's vaccine (choice D) is also for polio, not anthrax. Therefore, BCG vaccine is the most appropriate choice for preventing the spread of anthrax among animals in the countryside.