A patient with pancytopenia has a bone marrow aspiration from the left posterior iliac crest. Which action would be important for the nurse to take after the procedure?

Correct Answer: D

Rationale: The correct answer is D. Having the patient lie on the left side for 1 hour after a bone marrow aspiration helps to prevent bleeding by applying pressure to the site. This position helps to promote clotting and reduces the risk of hematoma formation. Elevating the head of the bed (choice A) is not necessary for this procedure. Applying a sterile 2-inch gauze dressing (choice B) is important but does not address the immediate post-procedure care. Using a half-inch sterile gauze to pack the wound (choice C) is not recommended as it may disrupt the clotting process.

Correct Answer: C

Rationale: The correct answer is C because a prothrombin time (PT) of 28 seconds indicates a prolonged clotting time, putting the client at risk for bleeding. This requires immediate assessment and intervention to prevent complications. Choice A (INR of 2.8) is within the therapeutic range for clients on anticoagulant therapy, so it does not require immediate attention. Choice B (platelet count of 128000/mm³) is low but not critically low enough to warrant immediate action unless there are signs of active bleeding. Choice D (red blood cell count of 5.1 million/L) is within normal limits and does not indicate an urgent issue.

Correct Answer: C

Rationale: Rationale: 1. Blinatumomab is designed to engage T cells to target CD19 antigen on B-lymphoblasts. 2. CD19 is a specific marker expressed on B cells, making it a target for Blinatumomab. 3. CD10 is not targeted by Blinatumomab and is commonly found on early B-cell precursors. 4. CD15 and CD20 are not targeted by Blinatumomab and have different functions unrelated to B-lymphoblasts. Summary: - CD19 is the correct answer as it is the specific target for Blinatumomab on B-lymphoblasts. - CD10, CD15, and CD20 are incorrect as they are not the targeted antigens for Blinatumomab and have different roles in immune function.

Correct Answer: C

Rationale: The correct answer is C: Nominal. The central line types in this study (port, PICC, TEC) are categorical and do not have a natural order or ranking. They are simply names or labels representing different types of central lines. This makes them fall under the nominal data structure category. Continuous data (choice A) would involve measurements with infinite possible values. Dichotomous data (choice B) would have only two categories. Ordinal data (choice D) would imply a natural ranking or order among the categories, which is not applicable in this context.

Correct Answer: C

Rationale: The correct answer is C because the infant's red cell findings of ovalocytes and polikilocytosis are consistent with hereditary elliptocytosis, which is caused by mutations in genes encoding spectrin. In this scenario, the inheritance pattern aligns with the infant receiving an alpha-spectrin mutation from both parents, leading to the observed erythrocyte abnormalities. This condition may improve over time due to compensatory mechanisms. Choice A (autosomal dominant ankyrin mutation causing hereditary spherocytosis) is incorrect because the clinical presentation and red cell morphology do not support a diagnosis of hereditary spherocytosis. Choice B (inherited band 3 variants and need for splenectomy) is incorrect as the infant's condition does not match the characteristics of hereditary spherocytosis requiring splenectomy. Choice D (PKLR variant and pyruvate kinase deficiency) is incorrect as the infant's red cell morphology is not indicative