ATI LPN
Medical Surgical Endocrine Quizlet Questions
Question 1 of 5
A client presents to the ED with a history of adrenal insufficiency. The following laboratory values are obtained: Na+ 130 mEq/L, K+ 5.6 mEq/L, and glucose 72 mg/dL. Which is the first request that the nurse anticipates?
Correct Answer: A
Rationale: Hyperkalemia (5.6 mEq/L) in adrenal insufficiency needs urgent correction; insulin/dextrose shifts K+ into cells.
Question 2 of 5
A client is admitted to the ICU with diagnosis of a brain tumor complicated by transient diabetes insipidus. Which client data related to this complication should the nurse expect? Select ONE that does not apply.
Correct Answer: A
Rationale: DI is a condition in which ADH is insufficiently produced or suppressed, resulting in polydipsia and polyuria (up to 20 L/day). Urine is copious and dilute with a low specific gravity (<1.005); fluid volume deficit can lead to dehydration, hypernatremia, high serum osmolality, and weight loss.
Question 3 of 5
The nurse cares for a client with Addison's disease who was involved in a motor vehicle accident and hospitalized for a fracture of the right femur. Which client information is most important to report to the PCP?
Correct Answer: A
Rationale: Significant BP drop in Addison's suggests adrenal crisis, a priority to report due to risk of shock.
Question 4 of 5
The nurse is caring for a client who has undergone a subtotal thyroidectomy. Which of the following should the nurse include in the client's plan of care?
Correct Answer: C
Rationale: Post-thyroidectomy, airway obstruction risk (e.g., hematoma) necessitates a tracheotomy set.
Question 5 of 5
The nurse is preparing to administer a regular insulin IV bolus to a client who has hyperglycemic-hyperosmolar state (HHS). The primary health care provider (PHCP) has prescribed an initial bolus dose of 0.1 unit/kg. The client weighs 198 pounds. How much regular insulin should the nurse administer to the client as an IV bolus?
Correct Answer: C
Rationale: 198 lbs ÷ 2.2 = 90 kg; 0.1 unit/kg × 90 kg = 9 units.