ATI LPN
ATI LPN Med Surg Level 3 Questions
Extract:
Question 1 of 5
A nurse is reinforcing discharge teaching for a client who will be taking warfarin (Coumadin) at home. Which of the following statements indicates that the client understands the risks while taking this medication?
Correct Answer: B
Rationale: Using an electric razor reduces bleeding risk, a key concern for clients on warfarin.
Question 2 of 5
A nurse is assisting with collecting data on a client who is on a continuous ECG monitor. The client's ECG tracing shows no identifiable P waves and an irregular ventricular rate. The nurse should recognize the client is experiencing which of the following cardiac dysrhythmias?
Correct Answer: C
Rationale: In atrial fibrillation, P waves are absent, and the ventricular rhythm is irregular. This matches the ECG description given in the question.
Question 3 of 5
A home health nurse is collecting data from a patient who has heart failure and notes the patient has had a weight gain of 1.8 kg, as well as generalized edema, since the last visit 3 days ago. Which of the following actions is a priority for the nurse to take?
Correct Answer: C
Rationale: Ensuring diuretic compliance is the priority to address fluid retention indicated by weight gain and edema.
Question 4 of 5
A nurse is caring for a client who has hypertension and is to start taking atenolol. The nurse should instruct the client to monitor for which of the following findings as an adverse effect of this medication?
Correct Answer: D
Rationale: Atenolol, a beta-blocker, slows down the heart rate and can lead to bradycardia (a heart rate that is too slow), which is a common adverse effect to monitor for.
Question 5 of 5
A nurse is preparing to administer potassium chloride 20 mEq. The amount available is potassium chloride liquid 40 mEq/15 mL. How many ml should the nurse administer? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.)
Correct Answer: 7.5 mL
Rationale: Desired dose is 20 mEq, available concentration is 40 mEq/15 mL. mL = (20 mEq ÷ 40 mEq) × 15 mL = 7.5 mL.