Correct Answer: A

Rationale: The correct answer is A: phenotype. A phenotype is the observable characteristics of an individual, which result from the interaction of their genotype with the environment. This interaction between genetics and the environment determines how genes are expressed and how traits are manifested in an individual. Choices B, C, and D are incorrect because chromosomes, alleles, and genotypes are components of an individual's genetic makeup, but they do not directly reflect the observable traits influenced by both genetics and the environment.

Correct Answer: A

Rationale: Monozygotic (MZ) twins share 100% of their genes because they originate from the same fertilized egg that splits into two, resulting in identical genetic material for both twins. Choice B (75%) is incorrect as it implies a partial genetic similarity, which is not the case for MZ twins. Choice C (50%) is incorrect as it suggests half of the genes are shared, which is applicable to dizygotic (DZ) twins, not MZ. Choice D (25%) is incorrect as it indicates minimal genetic sharing, which is not true for MZ twins.

Correct Answer: C

Rationale: The correct answer is C because in a client receiving magnesium sulfate, absent deep tendon reflexes can indicate magnesium toxicity, which requires immediate intervention to prevent serious complications. Choices A, B, and D are common postpartum occurrences that do not typically warrant immediate provider notification. A urinary output of 300 ml in 8 hours, abdominal cramping during breastfeeding, and frequent changing of perineal pads due to lochia rubra are within the expected range of postpartum recovery and do not indicate an urgent need for provider notification.

Correct Answer: B

Rationale: The correct answer is B: FALSE. Babies with fetal alcohol syndrome (FAS) are typically smaller than normal, with smaller brains and developmental issues. Choice A is incorrect because babies with FAS are not larger than normal. Choice C is incorrect as it does not accurately reflect the typical characteristics of babies with FAS. Choice D is incorrect as babies with FAS are not always larger than normal.

Correct Answer: B

Rationale: Misoprostol can be used for induction in clients with gestational diabetes mellitus. Choice A, a client with active genital herpes, is not a candidate for misoprostol induction due to the risk of viral shedding and transmission. Choice C, a client with a previous uterine incision, may be at risk for uterine rupture with misoprostol use. Choice D, a client with placenta previa, is not an appropriate candidate for misoprostol induction due to the risk of increased bleeding associated with the condition.