Questions 9

HESI LPN

HESI LPN Test Bank

Adult Health 2 Final Exam Questions

Question 1 of 5

A client is admitted with a diagnosis of pneumonia. Which intervention should the nurse implement to promote airway clearance?

Correct Answer: B

Rationale: Encouraging increased fluid intake is the most appropriate intervention to promote airway clearance in a client with pneumonia. Adequate hydration helps to thin respiratory secretions, making it easier for the client to cough up and clear the airways. Administering bronchodilators (Choice A) may help with bronchospasm but does not directly promote airway clearance. Chest physiotherapy (Choice C) can be beneficial in certain cases but may not be the initial intervention for promoting airway clearance. Providing humidified oxygen (Choice D) can help improve oxygenation but does not specifically target airway clearance in pneumonia.

Question 2 of 5

The nurse is caring for a client who has just returned from surgery with a urinary catheter in place. What is the most important action to prevent catheter-associated urinary tract infections (CAUTIs)?

Correct Answer: B

Rationale: The correct answer is to ensure the catheter bag is always below bladder level. This positioning helps prevent backflow of urine, reducing the risk of CAUTIs. Choice A, irrigating the catheter daily, is not recommended as it can introduce pathogens into the bladder. Changing the catheter too frequently (Choice C) can increase the risk of introducing pathogens. Administering prophylactic antibiotics (Choice D) is not the primary intervention for preventing CAUTIs and can lead to antibiotic resistance.

Question 3 of 5

A client is admitted with a diagnosis of diabetic ketoacidosis (DKA). Which laboratory finding is most indicative of this condition?

Correct Answer: C

Rationale: The correct answer is C: Positive urine ketones. In diabetic ketoacidosis (DKA), the body breaks down fat for energy due to a lack of insulin, leading to ketone production. Positive urine ketones are a hallmark laboratory finding in DKA as they directly reflect the presence of ketosis. Choice A, serum glucose of 180 mg/dL, may be elevated in DKA, but it is not specific to this condition. Choice B, blood pH of 7.30, often shows acidosis in DKA, but urine ketones are more specific to the presence of ketosis. Choice D, serum bicarbonate of 25 mEq/L, would typically be low in DKA due to acidosis rather than elevated.

Question 4 of 5

During a manic episode, what is the most appropriate intervention to implement first for a client with bipolar disorder?

Correct Answer: B

Rationale: During a manic episode, individuals with bipolar disorder may experience sensory overload and agitation. Providing a structured environment with minimal stimulation is the most appropriate initial intervention as it can help reduce overwhelming sensory input and promote a sense of calm. Engaging the client in a quiet activity (Choice A) may not be effective if the environment is still overstimulating. Continuous monitoring (Choice C) is important but may not be the first intervention needed. Adjusting lighting and noise levels (Choice D) can be helpful but may not address the core issue of sensory overload and agitation during a manic episode.

Question 5 of 5

The practical nurse is preparing to administer a prescription for cefazolin (Kefzol) 600 mg IM every six hours. The available vial is labeled, 'Cefazolin (Kefzol) 1 gram,' and the instructions for reconstitution state, 'For IM use add 2 ml sterile water for injection. Total volume after reconstitution = 2.5 ml.' When reconstituted, how many milligrams are in each milliliter of solution?

Correct Answer: A

Rationale: After reconstitution, the concentration of cefazolin solution is calculated by dividing the total amount of drug (600 mg) by the total volume after reconstitution (2.5 mL). This gives 600 mg / 2.5 mL = 240 mg/mL. However, the question asks for the concentration in each milliliter of solution after reconstitution, so we need to consider the final volume of 2.5 mL. Therefore, 240 mg/mL * 2.5 mL = 600 mg, which means each milliliter contains 240 mg of cefazolin. Therefore, after reconstitution, there are 400 mg of cefazolin in each milliliter of solution. Choices B, C, and D are incorrect as they do not accurately reflect the concentration after reconstitution.

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