HESI RN
HESI Medical Surgical Practice Quiz Questions
Question 1 of 5
Blood for arterial blood gas determinations is drawn from a client with pneumonia, and testing reveals a pH of 7.45, PCO2 of 30 mm Hg, and HCO3 of 19 mEq/L. The nurse interprets these results as indicative of:
Correct Answer: B
Rationale: The correct answer is 'Compensated respiratory alkalosis.' In this case, the client's pH is within the normal range (7.35-7.45), indicating compensation. The low PCO2 (30 mm Hg) suggests respiratory alkalosis, while the low HCO3 (19 mEq/L) is also consistent with a compensatory response. Therefore, the client has a primary respiratory alkalosis that is being compensated for by metabolic acidosis. Choices A, C, and D are incorrect because they do not fit the pattern of the given blood gas values, which indicate respiratory alkalosis with metabolic compensation.
Question 2 of 5
A client's baseline vital signs are temperature 98°F oral, pulse 74 beats/min, respiratory rate 18 breaths/min, and blood pressure 124/76 mm Hg. The client suddenly spikes a fever to 103°F. Which of the following respiratory rates would the nurse anticipate as part of the body's response to the change in client status?
Correct Answer: D
Rationale: When a client experiences a fever, there is an increase in body temperature, leading to a higher metabolic rate and oxygen demand. As a result, the respiratory rate typically increases to meet the body's increased oxygen needs. Therefore, in response to the fever spike from 98°F to 103°F, the nurse would anticipate a higher respiratory rate. Choices A, B, and C are incorrect because a decrease in body temperature, not an increase as seen in fever, would lead to a decrease in respiratory rate to conserve energy and oxygen consumption.
Question 3 of 5
A nurse reviews the urinalysis of a client and notes the presence of glucose. Which action should the nurse take?
Correct Answer: D
Rationale: Glucose normally is not found in the urine. The normal renal threshold for glucose is about 220 mg/dL, which means that a person whose blood glucose is less than 220 mg/dL will not have glucose in the urine. A positive finding for glucose on urinalysis indicates high blood sugar. The most appropriate action would be to perform a capillary artery glucose assessment. The client needs further evaluation for this abnormal result; therefore, documenting and continuing to monitor is not appropriate. Requesting a 24-hour urine test or reviewing the client's dietary selections will not assist the nurse to make a clinical decision related to this abnormality.
Question 4 of 5
A client has a urine specific gravity of 1.040. What action should the nurse take?
Correct Answer: D
Rationale: A urine specific gravity of 1.040 is higher than the normal range (1.005 to 1.030) and can indicate dehydration, decreased kidney blood flow, or the presence of antidiuretic hormone. In this situation, the priority action should be to increase the client's fluid intake to address the high specific gravity. Obtaining a urine culture, placing the client on restricted fluids, or assessing the creatinine level would not directly address the underlying issue of high urine specific gravity caused by dehydration or other factors.
Question 5 of 5
A nurse cares for a client with diabetes mellitus who is prescribed metformin (Glucophage) and is scheduled for an intravenous urography. Which action should the nurse take first?
Correct Answer: A
Rationale: Metformin can cause lactic acidosis and renal impairment as the result of an interaction with the dye. This drug must be discontinued for 48 hours before the procedure and not started again after the procedure until urine output is well established. The client's health care provider needs to provide alternative therapy for the client until the metformin can be resumed. Keeping the client NPO, checking the client's blood glucose, and administering intravenous fluids should be part of the client's plan of care, but are not the priority, as the examination should not occur while the client is still taking metformin.