HESI A2
HESI A2 Math Practice Questions
Question 1 of 5
If a marathon runner burns 2276 calories in 21.4 miles, what is their rate of calories burned per mile?
Correct Answer: B
Rationale: To find the rate of calories burned per mile, divide the total calories burned by the total miles run: 2276 · 21.4 ≈ 106.4 calories per mile. This calculation gives the average number of calories burned for each mile of the marathon. Choice A, 107.5, is incorrect as it does not match the precise calculation result. Choices C and D are also incorrect as they are not the accurate rate of calories burned per mile based on the given data.
Question 2 of 5
A circular bandage has a diameter of 6cm. What is the area covered by the bandage (area of a circle = πr^2)?
Correct Answer: C
Rationale: Rationale: - The formula for the area of a circle is A = πr^2, where r is the radius of the circle. - The diameter of the circular bandage is 6 cm, so the radius (r) is half of the diameter, which is 6/2 = 3 cm. - Substitute the radius (r = 3 cm) into the formula for the area of a circle: A = π(3)^2 = 9π cm^2. - Therefore, the area covered by the bandage is 9π cm^2.
Question 3 of 5
A diabetic patient's blood sugar is 180mg/dL. Their usual insulin dose is 1 unit per 40mg/dL above 100mg/dL. How much insulin should be administered?
Correct Answer: B
Rationale: Rationale: 1. Calculate the excess blood sugar above 100mg/dL: 180mg/dL - 100mg/dL = 80mg/dL. 2. Determine the insulin dose based on the patient's usual insulin dose: 80mg/dL / 40mg/dL = 2 units. 3. Add the calculated insulin dose to the patient's usual insulin dose: 1 unit (usual dose) + 2 units (calculated dose) = 3 units. Therefore, the correct answer is 3 units of insulin should be administered to the diabetic patient with a blood sugar level of 180mg/dL.
Question 4 of 5
What is the total surface area of a lampshade consisting of a cylindrical base (diameter 20cm, height 10cm) and a hemispherical top (same diameter as the base)?
Correct Answer: D
Rationale: To find the total surface area of the lampshade, first calculate the surface area of the cylinder and the hemisphere separately. 1. Surface area of the cylinder = 2πr² + 2πrh = 2π(10)² + 2π(10)(20) = 400π + 400π = 800π cm². 2. Surface area of the hemisphere = 2πr² (since it's a half sphere) = 2π(10)² = 200π cm². Adding both areas gives the total surface area: 800π + 200π = 1000π cm². Now, calculate the numerical value: 1000π ≈ 3141.59 cm², which is approximately equal to 2055 cm². Therefore, the correct answer is 2055 sq cm. Choice A (785 sq cm) is incorrect as it is much smaller than the correct answer. Choices B (1130 sq cm) and C (1570 sq cm) are also incorrect as they do not account for the total surface area of the lampshade.
Question 5 of 5
A decorative box has a rectangular base (20cm by 15cm) and a hemispherical top with the same diameter as the base. What is the total surface area of the box (excluding the base)?
Correct Answer: C
Rationale: To find the total surface area of the box excluding the base, calculate the lateral surface area of the rectangular base and the surface area of the hemisphere. The lateral surface area of the rectangular base is 2(20cm x 15cm) = 600 sq cm. The surface area of the hemisphere is 2πr^2, where r is half the diameter of the base, so r = 10cm. Thus, the surface area of the hemisphere is 2π(10cm)^2 = 200π sq cm ≈ 628.32 sq cm. Add the lateral surface area of the base and the surface area of the hemisphere: 600 sq cm + 628.32 sq cm ≈ 1228.32 sq cm. Therefore, the total surface area of the box is approximately 1228.32 sq cm, which is closest to 1325 sq cm (Choice C). Choices A, B, and D are incorrect as they do not represent the accurate calculation of the total surface area of the box.