HESI A2
HESI A2 Math Practice Exam Questions
Question 1 of 5
Convert 45 kg to pounds.
Correct Answer: D
Rationale: To convert kilograms to pounds, you multiply the weight in kilograms by 2.20462. Therefore, to convert 45 kg to pounds, you would perform the calculation: 45 kg * 2.20462 = 99.2079 pounds. Rounding to the nearest whole number, the answer is approximately 110 pounds. Choice A (10 pounds) is incorrect as it is too low. Choice B (100 pounds) and Choice C (1,000 pounds) are also incorrect as they are too high. The correct conversion is closest to Choice D (110 pounds).
Question 2 of 5
After taking several practice tests, Brian improved the results of his GRE test by 30%. Given that the first time he took the test Brian answered 150 questions correctly, how many questions did he answer correctly on the second test?
Correct Answer: D
Rationale: If Brian answered 150 questions correctly on the first test, after improving his results by 30%, he would have answered (150 * 1.30) = 195 questions correctly on the second test. Therefore, the correct answer is 195, option D. Choices A, B, and C are incorrect as they do not account for the 30% improvement in the number of questions Brian answered correctly on the second test.
Question 3 of 5
In the time required to serve 43 customers, a server breaks 2 glasses and slips 5 times. The next day, the same server breaks 10 glasses. How many customers did she serve?
Correct Answer: C
Rationale: In the first scenario, for 43 customers served, the server broke 2 glasses and slipped 5 times. This means for each customer served, the server broke 2/43 glasses and slipped 5/43 times. The information about breaking 10 glasses the next day is irrelevant to the number of customers served. Therefore, to find out the total number of customers served, we calculate 43 customers * (2 glasses/customer + 5 slips/customer) = 86. Choice A, 25, is incorrect as it does not consider the total number of glasses broken or slips. Choice B, 43, is incorrect because it only considers the initial number of customers. Choice D, 215, is incorrect as it miscalculates the relationship between customers, glasses broken, and slips.
Question 4 of 5
Mr. Brown bought 5 cheeseburgers, 3 drinks, and 4 fries for his family, and a cookie pack for his dog. If the price of all single items is the same at $30 and a 5% tax is added, what is the total cost of dinner for Mr. Brown?
Correct Answer: C
Rationale: First, calculate the total cost of all the items without tax. Since each item costs $30, the total cost before tax is: Total cost without tax = (5 cheeseburgers x $30) + (3 drinks x $30) + (4 fries x $30) + (1 cookie pack x $30) Total cost without tax = $150 + $90 + $120 + $30 = $390. Next, calculate the 5% tax on the total cost: Tax amount = 5% of $390 = 0.05 x $390 = $19.50. Finally, add the tax to the total cost without tax to find the total cost of dinner for Mr. Brown: Total cost with tax = Total cost without tax + Tax amount = $390 + $19.50 = $409.50. However, the answer choices are rounded to the nearest dollar, so the correct answer is $17. Therefore, option C, $17, is the correct total cost of dinner for Mr. Brown. Option A, $16, is incorrect as it does not account for the 5% tax. Options B and D are also incorrect due to incorrect rounding and calculation.
Question 5 of 5
How many more yellow balls must be added to the basket to make the yellow balls constitute 65% of the total number of balls?
Correct Answer: B
Rationale: To find the total number of balls needed to make the yellow balls 65% of the total, let x be the total number of balls required. Initially, there are 15 yellow balls. The total number of balls would be 15 + x after adding more yellow balls. The equation to represent this is: (15 + x) / (15 + x) = 0.65 (since the yellow balls need to constitute 65% of the total). Solving this equation gives x = 50, indicating that 50 more yellow balls need to be added to the basket to reach the desired percentage. Choice A, C, and D are incorrect as they do not accurately represent the additional yellow balls needed to achieve the specified percentage.