ATI TEAS Math Practice Test - Nurselytic

Questions 39

ATI TEAS 7

ATI TEAS 7 Test Bank

ATI TEAS Math Practice Test Questions

Question 1 of 5

There are 80 mg in 0.8 mL of Acetaminophen Concentrated Infant Drops. If the proper dosage for a four-year-old child is 240 mg, how many milliliters should the child receive?

Correct Answer: C

Rationale:
To find out how many milliliters the child should receive, divide the total required dosage of 240 mg by the concentration of the medication, which is 80 mg per 0.8 mL. 240 mg · 80 mg/mL = 3 mL. Since each dose is 0.8 mL, the total dosage for the child would be 3 doses x 0.8 mL per dose = 2.4 mL.
Therefore, the correct answer is 2.4 mL.
Choice A (0.8 mL) is the concentration of the medication, not the total dose.

Choices B (1.6 mL) and D (3.2 mL) are incorrect calculations that do not consider the concentration of the medication and the total required dosage correctly.

Question 2 of 5

Joshua has to earn more than 92 points on a state test to qualify for a scholarship. Each question is worth 4 points, and the test has 30 questions. Which inequality can be solved to determine the number of questions Joshua must answer correctly?

Correct Answer: D

Rationale: Joshua must answer more than 92 points' worth of questions. Since each question is worth 4 points, the inequality is 4x > 92.
Choice A (4x < 30) is incorrect as it represents that Joshua must answer less than 30 questions correctly, not earning more than 92 points.
Choice B (4x < 92) is incorrect as it signifies that Joshua must earn less than 92 points, which contradicts the requirement.
Choice C (4x > 30) is incorrect as it implies that Joshua must answer more than 30 questions correctly, but the threshold is 92 points, not 30 points.

Question 3 of 5

If Stella's current weight is 56 kilograms, which of the following is her approximate weight in pounds? (Note: 1 kilogram is approximately equal to 2.2 pounds.)

Correct Answer: A

Rationale:
To convert Stella's weight from kilograms to pounds, you multiply her weight in kilograms (56) by the conversion factor (2.2): 56 2.2 = 123.2 pounds. Since we need to find the approximate weight in pounds, the closest option is 123 pounds, making choice A the correct answer.

Choices B, C, and D are incorrect because they do not reflect the accurate conversion of Stella's weight from kilograms to pounds.

Question 4 of 5

A charter bus driver drove at an average speed of 65 mph for 305 miles. If he stops at a gas station for 15 minutes, then drives another 162 miles at an average speed of 80 mph, how long will it have been since he began the trip?

Correct Answer: D

Rationale:
To find the total time, we first calculate the time taken for the first leg of the trip by dividing the distance of 305 miles by the speed of 65 mph, which equals 4.69 hours. After that, we add the 15 minutes spent at the gas station, which is 0.25 hours. Next, we calculate the time taken for the second leg of the trip by dividing the distance of 162 miles by the speed of 80 mph, which equals 2.03 hours. Adding these times together (4.69 hours + 0.25 hours + 2.03 hours) gives us a total time of 6.97 hours.
Therefore, it will have been 6.97 hours since the driver began the trip.
Choice A is incorrect as it does not account for the time spent driving the second leg of the trip.
Choice B is incorrect as it only considers the time for the first leg of the trip and the time spent at the gas station.
Choice C is incorrect as it misses the time taken for the second leg of the trip.

Question 5 of 5

Simplify the following expression:

Correct Answer: A

Rationale:
To simplify the given expression, start by performing the division first: (2/3) · (4/15) = (2/3) (15/4) = 30/12 = 5/2. Next, multiply this result by 5/8: 5/2 5/8 = 25/16 = 1 9/16.
Therefore, the correct answer is A.
Choice B (1 1/4) is incorrect as it does not match the simplified result.
Choice C (2 1/8) is incorrect as it does not represent the simplified expression.
Choice D (2) is incorrect as it does not account for the fractions in the original expression.

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