Why is the stratified squamous epithelium found in the skin adapted for?

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ATI TEAS 7

ATI TEAS 7 Test Bank

TEAS Test 7 science Questions

Question 1 of 5

Why is the stratified squamous epithelium found in the skin adapted for?

Correct Answer: C

Rationale: The stratified squamous epithelium found in the skin is adapted for protection. This type of epithelium forms a tough, protective barrier against physical, chemical, and biological damage. Its multiple layers of cells help prevent the entry of pathogens and reduce water loss from the body, making it essential for shielding the underlying tissues. Choices A, B, and D are incorrect because stratified squamous epithelium is not specialized for absorption, secretion, or gas exchange. Instead, its primary function is to protect the underlying tissues and organs from external damage and dehydration.

Question 2 of 5

Scoliosis is a condition characterized by abnormal lateral curvature of the spine. Which part of the spine is most commonly affected?

Correct Answer: B

Rationale: Scoliosis most commonly affects the thoracic spine, which is the upper back region. While scoliosis can potentially affect any part of the spine, the thoracic spine is the most frequently involved area. This region is more commonly affected due to the natural structural curves of the spine and the biomechanics of the thoracic area. The cervical spine (neck) and lumbar spine (lower back) can also be affected by scoliosis, but the thoracic spine is the primary area of involvement in most cases. Therefore, the correct answer is B, as it is the part of the spine most commonly affected by scoliosis.

Question 3 of 5

A 10 kg box rests on a frictionless surface. A horizontal force of 20 N is applied to the box. What is the box's acceleration?

Correct Answer: B

Rationale: The acceleration of an object is given by the formula \(a = \frac{F}{m}\), where \(F\) is the net force acting on the object and \(m\) is the mass of the object. In this case, the net force acting on the box is 20 N, and the mass of the box is 10 kg. Plugging these values into the formula, we get \(a = \frac{20}{10} = 2\) m/s².

Question 4 of 5

A guitar string vibrates at a fundamental frequency of 440 Hz. What is the frequency of the second harmonic (first overtone)?

Correct Answer: C

Rationale: The second harmonic (first overtone) is twice the frequency of the fundamental frequency. Therefore, the frequency of the second harmonic is 440 Hz * 2 = 880 Hz. The second harmonic has a frequency that is one octave higher than the fundamental frequency, representing the first overtone of the vibrating string. Choice A (220 Hz) is incorrect as it represents half the fundamental frequency and is the second harmonic, not the first overtone. Choice B (440 Hz) is the fundamental frequency itself. Choice D (1760 Hz) is the frequency of the fourth harmonic, not the second harmonic.

Question 5 of 5

A light ray travels from air (refractive index 1.00) into water (refractive index 1.33). What happens to its speed and direction?

Correct Answer: C

Rationale: When a light ray travels from air (lower refractive index) to water (higher refractive index), its speed decreases due to the change in the medium. This is because light travels slower in denser mediums. As the light ray enters the denser medium, water in this case, it bends towards the normal (the line perpendicular to the surface of the water). This phenomenon is known as refraction. Choice A is incorrect as the speed of light decreases when entering a denser medium. Choice B is incorrect as the direction bends towards the normal, not away from it. Choice D is incorrect as the speed and direction of the light ray do change when moving from air to water.

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