Veronica has to create the holiday schedule for the neonatal unit at her hospital. She knows that 35% of the staff members will not be available because they are taking vacation days during the holiday. Of the remaining staff members who will be available, only 20% are certified to work in the neonatal unit. What percentage of the total staff is certified and available to work in the neonatal unit during the holiday?

Questions 34

ATI TEAS 7

ATI TEAS 7 Test Bank

TEAS Math Questions Questions

Question 1 of 5

Veronica has to create the holiday schedule for the neonatal unit at her hospital. She knows that 35% of the staff members will not be available because they are taking vacation days during the holiday. Of the remaining staff members who will be available, only 20% are certified to work in the neonatal unit. What percentage of the total staff is certified and available to work in the neonatal unit during the holiday?

Correct Answer: A

Rationale: After 35% of the staff is on vacation, 65% remain. Of these remaining staff, 20% are certified to work in the neonatal unit. To find the percentage of the total staff that is certified and available, we calculate 20% of the 65% remaining staff: 0.2 * 65% = 13%. Therefore, 13% of the total staff is certified and available to work in the neonatal unit during the holiday. The correct answer is 0.13. Choices B, C, and D are incorrect because they do not accurately represent the correct percentage calculation based on the given information.

Question 2 of 5

Out of 9 trips, a person chooses the longest route for 3 of them. What percentage of their trips is the longest route?

Correct Answer: B

Rationale: To find the percentage of trips where the person chose the longest route, divide the number of longest route trips (3) by the total number of trips (9) and multiply by 100. This gives (3/9) * 100 = 33.33%, which can be rounded to 33%. Therefore, the correct answer is B. Choice A (0.25), C (0.5), and D (0.75) are incorrect because they do not accurately represent the percentage of trips where the longest route was chosen based on the given information.

Question 3 of 5

In a city with a population of 51,623, 9.5% of the population voted for a new proposition. How many people approximately voted?

Correct Answer: B

Rationale: To find the number of people who voted, you need to calculate 9.5% of the total population of 51,623. 9.5% of 51,623 is approximately 0.095 x 51,623 = 4,999.85, which is rounded to approximately 5,000 people. Therefore, the correct answer is 5,000 people. Choice A, 3,000 people, is incorrect as it is lower than the calculated value. Choice C, 7,000 people, is incorrect as it is higher than the calculated value. Choice D, 10,000 people, is incorrect as it is much higher than the calculated value.

Question 4 of 5

A study was conducted where patients were divided into three groups: 1/2 in Group Alpha, 1/3 in Group Beta, and 1/6 in Group Gamma. Which group is the smallest?

Correct Answer: C

Rationale: The smallest group is Group Gamma, which had 1/6 of the total number of patients. To determine the smallest group, compare the fractions representing the portions of patients in each group. 1/6 is smaller than 1/3 and 1/2, making Group Gamma the smallest. Group Alpha and Group Beta have larger fractions of patients, making them larger groups compared to Group Gamma.

Question 5 of 5

A person drives 300 miles at 60 mph, then another 200 miles at 80 mph, with a 30-minute break. How long does the trip take?

Correct Answer: C

Rationale: To find the total time, we calculate the time taken for each segment: 300 miles at 60 mph = 300 miles · 60 mph = 5 hours; 200 miles at 80 mph = 200 miles · 80 mph = 2.5 hours. Adding these gives 5 hours + 2.5 hours = 7.5 hours. Converting the 30-minute break to hours (30 minutes · 60 = 0.5 hours), the total time taken is 7.5 hours + 0.5 hours = 8 hours. Therefore, the correct answer is not among the given choices. The rationale provided in the original question is incorrect as it does not account for the break time and has a calculation error in adding the individual times.

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