ATI TEAS 7
Math Practice TEAS Test Questions
Question 1 of 5
Joshua needs more than 92 points to qualify for a scholarship. Each question is worth 4 points, and there are 30 questions. What inequality determines how many questions he must answer correctly?
Correct Answer: B
Rationale: To determine the number of questions Joshua must answer correctly, we divide the total points required (92) by the points per question (4) to get 23. Since he needs more than 92 points, he must answer more than 23 questions correctly, which is represented by the inequality 4x > 92. Choices A, C, and D are incorrect because they do not accurately reflect the requirement for Joshua to answer more than 92 points' worth of questions.
Question 2 of 5
In Mrs. McConnell's classroom, there are 5 students with hazel eyes and 2 students with green eyes out of a total of 30 students. What percentage of the students have either hazel or green eyes?
Correct Answer: A
Rationale: To calculate the percentage of students with either hazel or green eyes, add the number of students with hazel and green eyes (5 + 2 = 7) and divide by the total number of students (30): 7 · 30 ≈ 0.23 or 23%. The correct answer is A, 0.23, which represents 23% of the total students. Choice B, 0.3, is incorrect as it corresponds to 30%, which is higher than the total number of students. Choice C, 0.47, is incorrect as it represents 47%, which is also higher than the total number of students. Choice D, 0.77, is incorrect as it corresponds to 77%, which is much higher than the total number of students.
Question 3 of 5
In Mrs. McConnell's classroom, there are 14 students with brown eyes and 2 students with green eyes. What is the ratio of students with brown eyes to students with green eyes?
Correct Answer: A
Rationale: The correct answer is A: 7:1. To find the ratio, divide the number of students with brown eyes (14) by the number of students with green eyes (2), which equals 7. Therefore, the ratio of students with brown eyes to students with green eyes is 7:1. Choice B (7:2) is incorrect as it does not accurately represent the ratio of students with brown eyes to green eyes. Choice C (14:2) is incorrect because the ratio should be simplified, and 14:2 simplifies to 7:1. Choice D (14:1) is incorrect as it does not consider the number of students with green eyes.
Question 4 of 5
During week 1, Cameron worked 5 shifts. During week 2, she worked twice as many shifts. During week 3, she added 4 more shifts. How many shifts did Cameron work in week 3?
Correct Answer: B
Rationale: To find out how many shifts Cameron worked in week 3, we first determine the shifts worked in weeks 1 and 2. In week 1, Cameron worked 5 shifts. In week 2, she worked twice as many shifts, which is 5 x 2 = 10 shifts. Adding the 4 more shifts in week 3, the total shifts worked in week 3 would be 5 (week 1) + 10 (week 2) + 4 (week 3) = 19 shifts. Therefore, the correct answer is 14 shifts (Option B), not 15 shifts (Option A), 16 shifts (Option C), or 17 shifts (Option D).
Question 5 of 5
What is the probability of consecutively pulling two more orange blocks, without replacement, from a bag containing 3 orange blocks, 5 green blocks, and 4 purple blocks?
Correct Answer: B
Rationale: To calculate the probability of consecutively pulling two more orange blocks without replacement, we first determine the probability of pulling an orange block on the first draw, which is 3/12 (3 orange blocks out of 12 total blocks). After removing one orange block, there are only 11 blocks left, so the probability of pulling another orange block on the second draw is 2/11. To find the combined probability, we multiply the probabilities together: (3/12) * (2/11) = 6/132 = 3/55. Therefore, the correct answer is B. Choice A (3/12) incorrectly simplifies the probability before calculating the second draw. Choice C (2/10) does not consider the specific number of orange blocks in the bag. Choice D (1/3) does not account for the reduced number of blocks after the first draw.