How does the Law of Conservation of Mass apply to this reaction: 2H₂ + O₂ → 2H₂O?

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ATI TEAS 7

ATI TEAS 7 Test Bank

ATI TEAS Science Practice Test Questions

Question 1 of 5

How does the Law of Conservation of Mass apply to this reaction: 2H₂ + O₂ → 2H₂O?

Correct Answer: D

Rationale: The Law of Conservation of Mass states that matter cannot be created or destroyed in a chemical reaction. In the given reaction, 2 moles of hydrogen combine with 1 mole of oxygen to form 2 moles of water. The total mass of the reactants (hydrogen and oxygen) is equal to the total mass of the products (water), meaning there is no decrease or increase in matter. The total mass of the system remains constant, demonstrating the conservation of mass. Choices A, B, and C are incorrect because the conservation of mass does not specifically relate to electrons, individual elements (like hydrogen), or the formation of new molecules; instead, it focuses on the overall mass of the system before and after the reaction.

Question 2 of 5

Which of the following best describes eosinophils?

Correct Answer: C

Rationale: Eosinophils are best described as a type of granulocyte found under mucous membranes that defends against multicellular parasites. They release toxic substances to combat parasitic infections and play a significant role in allergic reactions and asthma. Histamine secretion to stimulate inflammation is more characteristic of basophils, while high phagocytic activity and aggressiveness are features of neutrophils, not eosinophils. Describing eosinophils as the most abundant type of white blood cell that secretes toxic substances to pathogens is inaccurate since eosinophils specifically target multicellular parasites, not a broad range of pathogens.

Question 3 of 5

Which of the following accurately describes the measurements?

Correct Answer: B

Rationale: Accuracy refers to how close a measurement is to the true or accepted value, while precision refers to how close individual measurements are to each other. If the measurements are accurate but not precise, it means they consistently hit the target value but may vary in terms of how closely grouped they are. Choice B, 'They are accurate but not precise,' correctly describes the scenario where the measurements are on target but not consistently close to each other. Choice A is incorrect because it implies both accuracy and precision, which is not the case here. Choice C is incorrect because it suggests precision without accuracy, while choice D is incorrect as it indicates neither accuracy nor precision, which is not a typical scenario for measurements.

Question 4 of 5

Blood type is a trait determined by multiple alleles, with IA coding for A blood, IB coding for B blood, and i coding for O blood being recessive. If an individual with A heterozygosity and an O individual have a child, what is the probability that the child will have A blood?

Correct Answer: B

Rationale: When an A heterozygote individual (IAi) and an O individual (ii) have a child, there are four possible combinations of alleles that the child can inherit: IA from the A parent and i from the O parent; IA from the A parent and i from the O parent; i from the A parent and i from the O parent; i from the A parent and i from the O parent. Out of these combinations, 50% of the offspring will inherit the A allele from the A parent, resulting in A blood type. Therefore, the correct answer is 50%. Choice A is incorrect because the probability is not 25%. Choice C is incorrect as it overestimates the likelihood. Choice D is incorrect as it suggests a certainty which is not the case in genetics.

Question 5 of 5

How many mL of a 0 M stock solution of HCl should be added to water to create 250 mL of a 50 M solution of HCl?

Correct Answer: B

Rationale: To prepare 250 mL of a 50 M solution of HCl, the formula V1 x C1 = V2 x C2 is used, where V1 is the volume of the stock solution, C1 is the concentration of the stock solution, V2 is the final volume of the desired solution, and C2 is the final concentration of the desired solution. Given V1 x 0 M = 250 mL x 50 M, solving for V1 results in V1 = (250 mL x 50 M) / 0 M = 32 mL. Therefore, 32 mL of the 0 M stock solution of HCl needs to be added to water to create a 250 mL solution of 50 M HCl. Choices A, C, and D are incorrect because they do not represent the accurate volume required for the dilution calculation based on the given concentrations and volumes in the problem.

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