ATI TEAS 7
TEAS 7 Math Practice Test Questions
Question 1 of 9
Between the years 2000 and 2010, the number of births in the town of Daneville increased from 1432 to 2219. What is the approximate percent increase in the number of births?
Correct Answer: A
Rationale: To calculate the percent increase, subtract the initial value from the final value, which gives 2219 - 1432 = 787. Then, divide the increase (787) by the initial value (1432) and multiply by 100 to get the percentage: (787/1432) * 100 = 55%. Therefore, the approximate percent increase in the number of births is 55%. Choice B, 36%, is incorrect because it does not match the calculated increase. Choice C, 64%, is incorrect as it is higher than the actual percentage. Choice D, 42%, is incorrect as it is lower than the actual percentage.
Question 2 of 9
Simplify the following expression: 5 x 3 · 9 x 4
Correct Answer: A
Rationale: To simplify the expression 5 x 3 · 9 x 4, first perform the multiplications and divisions from left to right: 5 x 3 = 15 and 9 x 4 = 36. So, the expression becomes 15 · 36. When dividing fractions, multiply the first fraction by the reciprocal of the second fraction. Hence, 15 · 36 = 15/36. To simplify the fraction further, find the greatest common divisor, which is 3. Divide both the numerator and denominator by 3 to get the final result: 15/36 = 5/12. Therefore, the correct answer is A. Choices B, C, and D are incorrect because they do not represent the correct simplification of the given expression.
Question 3 of 9
Between the years 2000 and 2010, the number of births in the town of Daneville increased from 1432 to 2219. What is the approximate percent increase in the number of births?
Correct Answer: A
Rationale: To calculate the percent increase, subtract the initial value from the final value, which gives 2219 - 1432 = 787. Then, divide the increase (787) by the initial value (1432) and multiply by 100 to get the percentage: (787/1432) * 100 = 55%. Therefore, the approximate percent increase in the number of births is 55%. Choice B, 36%, is incorrect because it does not match the calculated increase. Choice C, 64%, is incorrect as it is higher than the actual percentage. Choice D, 42%, is incorrect as it is lower than the actual percentage.
Question 4 of 9
During January, Dr. Lewis worked 20 shifts. During February, she worked three times as many shifts as she did during January. During March, she worked half the number of shifts she worked during February. Which equation below describes the number of shifts Dr. Lewis worked in March?
Correct Answer: B
Rationale: During January, Dr. Lewis worked 20 shifts. Shifts for January = 20. During February, she worked three times as many shifts as she did during January. Shifts for February = (20)(3) = 60. During March, she worked half the number of shifts she worked in February. Shifts for March = (60)(1/2) = 30. Therefore, the correct equation to describe the number of shifts Dr. Lewis worked in March is 'shifts = (20)(3)(1/2)', representing the calculation based on the given scenario. Choices A, C, and D do not accurately represent the correct mathematical relationship between the shifts worked in the different months, making them incorrect.
Question 5 of 9
Lauren must travel a distance of 1,480 miles to get to her destination. She plans to drive approximately the same number of miles per day for 5 days. Which of the following is a reasonable estimate of the number of miles she will drive per day?
Correct Answer: C
Rationale: To estimate the number of miles Lauren will drive per day, the total distance can be rounded to 1,500 miles. Divide this by the number of days she plans to drive, which is 5. 1,500 miles / 5 days = 300 miles per day. Therefore, a reasonable estimate for the number of miles she will drive per day is 300. Choice A (240 miles) is too low, Choice B (260 miles) is slightly low, and Choice D (340 miles) is too high when considering the total distance and the number of days Lauren plans to drive.
Question 6 of 9
A lab technician took 500 milliliters of blood from a patient. The technician used 1/6 of the blood for further tests. How many milliliters of blood were used for further tests? Round your answer to the nearest hundredth.
Correct Answer: C
Rationale: To find 1/6 of 500, multiply 500 by 1/6: (500)(1/6) = 500/6 = 83.33. Converting the fraction to a decimal gives 83.33. Rounding this to the nearest hundredth results in 83.33. Therefore, 83.33 milliliters of blood were used for further tests. Choice A is incorrect as it does not consider the decimal value of the fraction. Choice B is incorrect as it rounds to the tenths place, not the nearest hundredth. Choice D is incorrect as it rounds up unnecessarily, as the correct answer should be rounded to 83.33.
Question 7 of 9
Robert is planning to drive 1,800 miles on a cross-country trip. If his car gets 30 miles per gallon and his tank holds 12 gallons of gas, how many tanks of gas will he need to complete the trip?
Correct Answer: B
Rationale: To find out how many tanks of gas Robert needs for the 1,800-mile trip, first, we calculate the distance his car can travel on a full tank: 30 miles per gallon 12 gallons = 360 miles per tank. Next, divide the total trip distance by the distance per tank: 1,800 miles · 360 miles per tank = 5 tanks. Therefore, Robert will need 5 tanks of gas to complete the cross-country trip. Choices A, C, and D are incorrect as they do not accurately calculate the number of tanks needed based on the given information.
Question 8 of 9
As part of a study, a set of patients will be divided into three groups. 4/15 of the patients will be in Group Alpha, 2/5 in Group Beta, and 1/3 in Group Gamma. Order the groups from smallest to largest, according to the number of patients in each group.
Correct Answer: B
Rationale: The correct order is Group Alpha, Group Gamma, Group Beta based on the common denominators of the fractions. To determine the order from smallest to largest, compare the fractions' numerators since the denominators are different. Group Alpha has 4/15 patients, Group Gamma has 1/3 patients, and Group Beta has 2/5 patients. Comparing the fractions' numerators, the order from smallest to largest is Group Alpha (4), Group Gamma (1), and Group Beta (2). Therefore, the correct order is Group Alpha, Group Gamma, Group Beta. Choice A is incorrect as it lists Group Beta before Group Gamma. Choice C is incorrect as it lists Group Gamma before Group Alpha. Choice D is incorrect as it lists Group Beta before Group Gamma, which is not in ascending order based on the number of patients.
Question 9 of 9
Within a nursing program, 25% of the class wanted to work with infants, 60% wanted to work with the elderly, 10% wanted to assist general practitioners, and the rest were undecided. What fraction of the class wanted to work with the elderly?
Correct Answer: C
Rationale: To find the fraction of the class wanting to work with the elderly, we convert the percentage to a fraction. 60% can be written as 60/100, which simplifies to 3/5. Therefore, 3/5 of the class wanted to work with the elderly. Choice A (1/4), choice B (1/10), and choice D (1/20) do not represent the fraction of the class wanting to work with the elderly, making them incorrect.